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MIDI mapping in logic


mharris

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Hi people,

 

My first post here! What a quality resource...

 

Anyway, down to business.. I have a midi keyboard which includes a few rotary midi controllers which generally I don’t use (as I have an additional midi controller). The problem is that occasionally I might accidentally knock one of the controls on the keyboard and I'll notice a parameter move like panning or filter cuttoff. - This gets a bit annoying and obviously I'd like to stop this.

 

I've looked at the midi assignments in Logic preferences and there aren't any assigned. So im guessing that the keyboard is broadcasting the standard midi CC data for these changes?

 

I can reconfigure the keyboard, but how do I know which CC numbers are free and not mapped to parameters in Logic?

 

Thanks for any help.

Martyn.

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No thers no option to turn them off. They can only be configured to specify which midi channel they transmit on and which midi CC number.

 

Really I'd still like them to be active, cause I do map them occasionly I just dont want them to be assigned to other logic parameters in the mean time.

 

Where can I find a list of the midi CC numbers and which parameters they map to in Logic?? Cant see it anywhere in the manual...

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You need to make a filter in the enviroment filter out the CC numbers with a filter, on the midi channel you use for the KB.

Helps and worx.

( yuo need more than one "midi channel")

 

Hi ecozyz, thanks for your help. I dont know much about filtering midi within the environment, but would this not mean that these controllers would then be unusable?

 

I want to keep them enabled so I can assign them "ad-hoc" if I run out of rotary's on my other controller. Surely there must be an unused CC number that isn't assigned to anything within logic? If so how do I find out which number?

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Logic Cafe has a decent environment beginner tutorial:

 

http://www.logic-cafe.com/Article_View.asp?ID=37;CategoryID=1

 

that might help ... altho it doesn't get as far as MIDI filtering.

 

Some filtering can be done in menuitem:

File > Project Settings > MIDI

 

There's a brief paragraph here:

http://logicfaq.omega-art.com/html/faq16.htm

that sketches out the steps to use Transformer to filter volume (CC7).

 

As for re-assigning incoming MIDI CC's, I wonder if the "control surfaces support" manual would help? I'd like to hear from anyone using CSS to route incoming MIDI from a keyboard controller.

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Ok, I found this page on midi.org http://www.midi.org/about-midi/table3.shtml

 

It lists the Control change messages and their associated numbers. It seems to be right because the control on my keyboard that is set to output CC 10 does indeed adjust the pan of the selected track.

 

So am I right in thinking that Logic in its default setup is configured to respond to these standardised mappings?? If this is correct, why is there nothing about this in the manual?

 

 

I dont fully understand this table, so perhaps someone could explain how I should set up my keyboard so that the controllers aren't mapped to anything in Logic? Do I just pick one of the numbers that is listed as "Undefined" ??

 

Thanks people.

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I dont fully understand this table, so perhaps someone could explain how I should set up my keyboard so that the controllers aren't mapped to anything in Logic? Do I just pick one of the numbers that is listed as "Undefined"

Not really. For example, have a look at Logic's "Instruments and Effects" manual. In particular for the ES 1 there is a "MIDI Controller List" showing which CC numbers are used for the parameters. But unfortunately it seems the only instrument which is properly documented.

.

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Ok so Logic defines its own mappings to each parameter in each instrument :x

 

So back to the original question.. How can I "initilise" the controlls on the keyboard so that they aren't mapped to any parameter in logic and are therefore free to be mapped as I need them.

 

Im finding it hard to believe that a midi control on my keyboard is always mapped to a parameter somewhere. Surely someone must have a solution to this simple problem..

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